diff --git a/pascal.cpp b/pascal.cpp
index 7d2495d..0dc79d9 100644
--- a/pascal.cpp
+++ b/pascal.cpp
@@ -11,14 +11,14 @@ int main() {
 		
 		int N;
 		cin >> N;
-		if (N <= 31) {
-			// if N <= 31 then just use naïve method
+		if (N <= 30) {
+			// if N <= 30 then just use naïve method
 			for (int i = 0; i < N; ++i) cout << i + 1 << " " << 1 << '\n';
 		}
 		else {
-			// first we try to make N - 31
-			int sum = 0, side = 0, goal = N - 31;
-			for (int i = 0; i < 31; ++i) {
+			// first we try to make N - 30
+			int sum = 0, side = 0, goal = N - 30;
+			for (int i = 0; i < 30; ++i) {
 				cout << i + 1 << " " << (side ? i + 1 : 1) << '\n';
 
 				// each row sums to 2 ^ (i + 1)
@@ -32,7 +32,8 @@ int main() {
 				else ++sum;
 			}
 
-			for (int i = 31; sum < N; ++i, ++sum) cout << i + 1 << ' ' << (side ? i + 1 : 1) << '\n';
+			// we've undershot so we still need to walk down until our sum is N
+			for (int i = 30; sum < N; ++i, ++sum) cout << i + 1 << ' ' << (side ? i + 1 : 1) << '\n';
 		}
 	}
 }
\ No newline at end of file
diff --git a/pattern.cpp b/pattern.cpp
index c8f4403..aceee5f 100644
--- a/pattern.cpp
+++ b/pattern.cpp
@@ -2,49 +2,48 @@
 using namespace std;
 
 int main() {
-    if (fopen("in", "r")) freopen("in", "r", stdin), freopen("out", "w", stdout);
+	if (fopen("in", "r")) freopen("in", "r", stdin), freopen("out", "w", stdout);
 
-    int T;
-    cin >> T;
-    for (int t = 1; t <= T; ++t) {
-        cout << "Case #" << t << ": ";
-        
-        int N;
-        cin >> N;
-        string P[55];
-        for (int i = 0; i < N; ++i) cin >> P[i];
-        
-        string l, m, r; // left, middle, end parts of final answer
-        bool ans = 1; // flag so we can quickly break when no solution exists
-        for (int i = 0; i < N && ans; ++i) {
-            // tokenize string
-            vector<string> parts;
-			parts.push_back("");
-            for (auto& c : P[i]) {
-                if (c == '*') parts.push_back(""); // add new string
-                else parts.back() += c; // add c to current string
-            }
-            
-            string& s = parts.front(); // leftmost part
-            for (int j = 0; j < s.size() && ans; ++j) {
-                if (j >= l.size()) l.push_back(s[j]); // extend l
-                else if (s[j] != l[j]) ans = 0; // s doesn't match with current l
-            }
-            
-            s = parts.back(); // rightmost part
-            reverse(s.begin(), s.end());
-            for (int j = 0; j < s.size() && ans; ++j) {
-                if (j >= r.size()) r.push_back(s[j]); // extend r
-                else if (s[j] != r[j]) ans = 0; // s doesn't match with current r
-            }
-            
-            // add other parts to the middle string
-            for (int j = 1; j < parts.size() - 1 && ans; ++j) m += parts[j];
-        }
+	int T;
+	cin >> T;
+	for (int t = 1; t <= T; ++t) {
+		cout << "Case #" << t << ": ";
 		
-        reverse(r.begin(), r.end());
-        
+		int N;
+		cin >> N;
+		string P[55]; // patterns
+		for (int i = 0; i < N; ++i) cin >> P[i];
+		
+		string l, m, r; // left, middle, end parts of final answer
+		bool ans = 1; // flag so we can quickly break when no solution exists
+		for (int i = 0; i < N && ans; ++i) {
+			// tokenize string
+			vector<string> parts;
+			parts.push_back("");
+			for (auto& c : P[i]) {
+				if (c == '*') parts.push_back(""); // add new string
+				else parts.back() += c; // add c to current string
+			}
+			
+			string& s = parts.front(); // leftmost part
+			for (int j = 0; j < s.size() && ans; ++j) {
+				if (j >= l.size()) l.push_back(s[j]); // extend l
+				else if (s[j] != l[j]) ans = 0; // s doesn't match with current l
+			}
+			
+			s = parts.back(); // rightmost part
+			reverse(s.begin(), s.end());
+			for (int j = 0; j < s.size() && ans; ++j) {
+				if (j >= r.size()) r.push_back(s[j]); // extend r
+				else if (s[j] != r[j]) ans = 0; // s doesn't match with current r
+			}
+			
+			// add other parts to the middle string
+			for (int j = 1; j < parts.size() - 1 && ans; ++j) m += parts[j];
+		}
+
 		// Creates at most ≈5000 < 10000 characters
-        cout << (ans ? l + m + r : "*") << '\n';
-    }
+		reverse(r.begin(), r.end());
+		cout << (ans ? l + m + r : "*") << '\n';
+	}
 }
\ No newline at end of file
diff --git a/square.cpp b/square.cpp
index 7714056..0ce2afe 100644
--- a/square.cpp
+++ b/square.cpp
@@ -8,7 +8,7 @@ typedef long long ll;
 constexpr int dx[4] = { 1, 0, -1, 0 }, dy[4] = { 0, 1, 0, -1 };
 
 int S[100001]; // skill levels
-vector<int> neighbor[100001]; // vector of neighbors for each competitor
+int neighbor[100001][4]; // array of neighbors for each competitor
 
 int main() {
 	if (fopen("in", "r")) freopen("in", "r", stdin), freopen("out", "w", stdout);
@@ -19,7 +19,7 @@ int main() {
 
 		int R, C; cin >> R >> C;
 		ll ans = 0, sum = 0;
-		vector<int> check; // set of candidate competitors to check
+		vector<int> check; // vector of candidate competitors to check
 		for (int i = 0; i < R; ++i) {
 			for (int j = 0; j < C; ++j) {
 				cin >> S[i * C + j]; sum += S[i * C + j];
@@ -35,7 +35,6 @@ int main() {
 		// precompute neighbors
 		for (int i = 0; i < R; ++i) {
 			for (int j = 0; j < C; ++j) {
-				neighbor[i * C + j].resize(4);
 				for (int d = 0; d < 4; ++d) {
 					int x = i + dx[d], y = j + dy[d]; // get neighbor
 					neighbor[i * C + j][d] = valid(x, y) ? x * C + y : -1;