--- id: dfs title: Depth First Search author: Siyong Huang prerequisites: - Bronze - Introduction to Graphs description: A way to traverse a graph using recursion. frequency: 4 --- import { Problem } from "../models"; export const metadata = { problems: { sample: [ new Problem("CSES", "Building Roads", "1666", "Intro", false, ["DFS"]), ], tree: [ new Problem("CSES", "Subordinates", "1674", "Intro", false, ["Tree", "DFS"]), new Problem("Silver", "Mootube", "788", "Easy", false, ["Tree", "DFS"]), new Problem("CF", "Journey", "contest/839/problem/C", "Easy", false, ["Tree", "DFS"]), new Problem("CF", "PolandBall & Forest", "problemset/problem/755/C", "Easy", false, ["Tree", "DFS"]), new Problem("CSES", "Tree Diameter", "1131", "Normal", false, ["Tree", "DFS"]), new Problem("CSES", "Tree Distances I", "1132", "Normal", false, ["Tree", "DFS"]), new Problem("CSES", "Tree Distances II", "1133", "Normal", false, ["Tree", "DFS"]), new Problem("CF", "Wizard's Tour", "contest/860/problem/D", "Normal", false, ["Tree", "DFS"]), new Problem("POI", "Hotels", "https://szkopul.edu.pl/problemset/problem/gDw3iFkeVm7ZA3j_16-XR7jI/site/?key=statement", "Normal", false, ["Tree", "DFS"]), new Problem("HE", "Birthday Gifts", "https://www.hackerearth.com/practice/math/combinatorics/inclusion-exclusion/practice-problems/algorithm/mancunian-and-birthday-gifts-d44faa15/description/", "Normal", false, ["Tree", "PIE"], ""), new Problem("CSA", "Tree Construction", "contest/860/problem/D", "Hard", false, ["Tree", "DFS"], "several cases"), ], general: [ new Problem("CF", "Bear & Friendship", "problemset/problem/771/A", "Easy", false, ["DFS"]), new Problem("Silver", "Closing the Farm", "644", "Easy", false, ["DFS"]), new Problem("Silver", "Moocast", "668", "Easy", false, ["DFS"]), new Problem("Silver", "Fence Planning", "944", "Easy", false, ["DFS"]), new Problem("Kattis", "Birthday Party", "birthday", "Easy", false, ["DFS"], "DFS with each edge removed"), new Problem("Silver", "Milk Visits", "968", "Normal", false, ["DFS"]), new Problem("Silver", "Milk Pails", "620", "Normal", false, ["DFS"]), new Problem("Silver", "Wormhole Sort", "992", "Normal", false, ["DFS", "Binary Search"]), new Problem("Silver", "Moo Particle", "1040", "Normal", false, ["Sorting"]), ], bipsample: [ new Problem("CSES", "Building Teams", "1668", "Easy", false, ["Bipartite"]), ], bip: [ new Problem("CF", "Bipartiteness", "contest/862/problem/B", "Easy", false, ["Bipartite"]), new Problem("Silver", "The Great Revegetation", "920", "Easy", false, ["Bipartite"]), ], } }; ## Tutorial - Recommended: - CPH 12.1 (DFS), 14 (Tree algorithms) - [PAPS 12.2](https://www.csc.kth.se/~jsannemo/slask/main.pdf) - [CSAcademy DFS](https://csacademy.com/lesson/depth_first_search/) - Additional: - [CPC.7](https://github.com/SuprDewd/T-414-AFLV/tree/master/07_graphs_1) - [cp-algo DFS](https://cp-algorithms.com/graph/depth-first-search.html) - hard to parse if this is your first time learning about DFS - [Topcoder Graphs Pt 2](https://www.topcoder.com/community/data-science/data-science-tutorials/introduction-to-graphs-and-their-data-structures-section-2/) ### Problems - Trees - General ## Graph Two-Coloring *Graph two-coloring* refers to assigning a boolean value to each node of the graph, dictated by the edge configuration The most common example of a two-colored graph is a *bipartite graph*, in which each edge connects two nodes of opposite colors. ### Tutorial - CPH 12.3 - [cp-algo - bipartite check](https://cp-algorithms.com/graph/bipartite-check.html) - Uses BFS, but DFS accomplishes the same task The idea is that we can arbitrarily label a node and then run DFS. Every time we visit a new (unvisited) node, we set its color based on the edge rule. When we visit a previously visited node, check to see whether its color matches the edge rule. For example, an implementation of coloring a bipartite graph is shown below. ```cpp //UNTESTED bool is_bipartite = true; void dfs(int node) { visited[node] = true; for(int u:adj_list[node]) if(visited[u]) { if(color[u] == color[node]) is_bipartite = false; } else { color[u] = !color[node]; dfs(u); } } ``` ### Problems