180 lines
No EOL
6.7 KiB
Text
180 lines
No EOL
6.7 KiB
Text
---
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id: intro-ordered
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title: "Introduction to Ordered Sets"
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author: Darren Yao, Benjamin Qi
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prerequisites:
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- Bronze - Unordered Maps & Sets
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description: ""
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frequency: 2
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---
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import { Problem } from "../models";
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export const metadata = {
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problems: {
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standard: [
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new Problem("CSES", "Concert Tickets", "1091", "Easy", false, ["iterators"], "just do upper_bound"),
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new Problem("CSES", "Traffic Lights", "1163", "Normal", false, ["set"], "just insert into set one at a time"),
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],
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}
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};
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<resources>
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<resource source="CPH" title="4.2 to 4.4: Data Structures" starred>Sets, Maps, Set Iterators</resource>
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</resources>
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<br />
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In **ordered** sets and maps, the entries are sorted in order of key. Insertions, deletions, and searches are all $O(\log N)$, where $N$ is the number of elements in the set or map. Accessing or removing the next key higher or lower than some input $k$ is also supported.
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## Ordered Sets
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<code-comment lang="cpp">
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As well as those supported by `unordered_set`, the ordered set also allows four additional operations: `begin()`, which returns an iterator to the lowest element in the set, `end()`, which returns an iterator to the highest element in the set, `lower_bound`, which returns an iterator to the least element greater than or equal to some element `k`, and `upper_bound`, which returns an iterator to the least element strictly greater than some element `k`.
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</code-comment>
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```cpp
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set<int> s;
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s.insert(1); // [1]
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s.insert(14); // [1, 14]
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s.insert(9); // [1, 9, 14]
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s.insert(2); // [1, 2, 9, 14]
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cout << *s.upper_bound(7) << '\n'; // 9
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cout << *s.upper_bound(9) << '\n'; // 14
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cout << *s.lower_bound(5) << '\n'; // 9
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cout << *s.lower_bound(9) << '\n'; // 9
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cout << *s.begin() << '\n'; // 1
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auto it = s.end();
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cout << *(--it) << '\n'; // 14
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s.erase(s.upper_bound(6)); // [1, 2, 14]
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```
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<code-comment lang="java">
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As well as those supported by the unordered set, the ordered set also allows four additional operations: `first`, which returns the lowest element in the set, `last`, which returns the highest element in the set, `lower`, which returns the greatest element strictly less than some element, and `higher`, which returns the least element strictly greater than it.
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</code-comment>
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```java
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TreeSet<Integer> set = new TreeSet<Integer>();
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set.add(1); // [1]
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set.add(14); // [1, 14]
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set.add(9); // [1, 9, 14]
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set.add(2); // [1, 2, 9, 14]
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System.out.println(set.higher(7)); // 9
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System.out.println(set.higher(9)); // 14
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System.out.println(set.lower(5)); // 2
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System.out.println(set.first()); // 1
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System.out.println(set.last()); // 14
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set.remove(set.higher(6)); // [1, 2, 14]
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System.out.println(set.higher(23); // ERROR, no such element exists
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```
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One limitation of the ordered set is that we can't efficiently access the $k^{th}$ largest element in the set, or find the number of elements in the set greater than some arbitrary $x$. These operations can be handled using a data structure called an **order statistic tree** (see Gold - Point Update Range Sum).
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## Ordered Maps
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### C++
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The ordered map supports all of the operations that an unordered map supports, and additionally supports `lower_bound` and `upper_bound`, returning the iterator pointing to the lowest entry not less than the specified key, and the iterator pointing to the lowest entry strictly greater than the specified key respectively.
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```cpp
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map<int, int> m;
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m[3] = 5; // [(3, 5)]
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m[11] = 4; // [(3, 5); (11, 4)]
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m[10] = 491; // [(3, 5); (10, 491); (11, 4)]
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cout << m.lower_bound(10)->first << " " << m.lower_bound(10)->second << '\n'; // 10 491
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cout << m.upper_bound(10)->first << " " << m.upper_bound(10)->second << '\n'; // 11 4
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m.erase(11); // [(3, 5); (10, 491)]
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if (m.upper_bound(10) == m.end())
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{
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cout << "end" << endl; // Prints end
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}
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```
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### Java
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The ordered map supports all of the operations that an unordered map supports, and additionally supports `firstKey` / `firstEntry` and `lastKey` /` lastEntry`, returning the lowest key/entry and the highest key/entry, as well as `higherKey` /` higherEntry` and `lowerKey` / `lowerEntry`, returning the lowest key/entry strictly higher than the specified key, or the highest key/entry strictly lower than the specified key.
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```java
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TreeMap<Integer, Integer> map = new TreeMap<Integer, Integer>();
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map.put(3, 5); // [(3, 5)]
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map.put(11, 4); // [(3, 5); (11, 4)]
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map.put(10, 491); // [(3, 5); (10, 491); (11, 4)]
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System.out.println(map.firstKey()); // 3
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System.out.println(map.firstEntry()); // (3, 5)
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System.out.println(map.lastEntry()); // (11, 4)
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System.out.println(map.higherEntry(4)); // (10, 491)
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map.remove(11); // [(3, 5); (10, 491)]
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System.out.println(map.lowerKey(4)); // 3
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System.out.println(map.lowerKey(3)); // ERROR
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```
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## Multisets
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Lastly, there is the multiset, which is essentially a sorted set that allows multiple copies of the same element.
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### C++
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In addition to all of the regular set operations, the multiset `count()` method returns the number of times an element is present in the multiset. However, this method takes time **linear** in the number of matches so you shouldn't use it in a contest.
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The `begin()`, `end()`, `lower_bound()`, and `upper_bound()` operations work the same way they do in the normal sorted set.
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**Warning:** If you want to remove a value *once*, make sure to use `multiset.erase(multiset.find(val))` rather than `multiset.erase(val)`. The latter will remove *all* instances of `val`.
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```cpp
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multiset<int> ms;
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ms.insert(1); // [1]
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ms.insert(14); // [1, 14]
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ms.insert(9); // [1, 9, 14]
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ms.insert(2); // [1, 2, 9, 14]
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ms.insert(9); // [1, 2, 9, 9, 14]
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ms.insert(9); // [1, 2, 9, 9, 9, 14]
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cout << ms.count(4) << '\n'; // 0
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cout << ms.count(9) << '\n'; // 3
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cout << ms.count(14) << '\n'; // 1
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ms.erase(ms.find(9));
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cout << ms.count(9) << '\n'; // 2
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ms.erase(9);
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cout << ms.count(9) << '\n'; // 0
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```
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### Java
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While there is no `Multiset` in Java, we can implement one using the `TreeMap` from values to their respective frequencies. We declare the `TreeMap` implementation globally so that we can write functions for adding and removing elements from it.
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```java
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static TreeMap<Integer, Integer> multiset = new TreeMap<Integer, Integer>();
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public static void main(String[] args){
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...
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}
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static void add(int x){
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if(multiset.containsKey(x)){
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multiset.put(x, multiset.get(x) + 1);
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} else {
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multiset.put(x, 1);
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}
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}
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static void remove(int x){
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multiset.put(x, multiset.get(x) - 1);
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if(multiset.get(x) == 0){
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multiset.remove(x);
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}
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}
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```
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The `first`, `last`, `higher`, and `lower` operations still function as intended; just use `firstKey`, `lastKey`, `higherKey`, and `lowerKey` respectively.
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## Using Iterators
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(prev(), next())
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## Standard
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<problems-list problems={metadata.problems.standard} /> |